| 
					
					
					 Invaded Zone Water Saturation From
					SHALLOW
					Resistivity Calculate invaded zone water saturation (Sxo) using the same method
                as used to calculate water saturation in the un-invaded zone (Sw).
                To do this, replace the following terms in any water saturation
                equation given earlier in this Chapter:
 
 RESD by RESS
 RW@FT by RMF@FT
 RSH by RSHS
 Sw by Sxo
 Where:RESD = deep resistivity (ohm-m)
 RESS = shallow resistivity (ohm-m)
 RMF@FT = mud filtrate at form temperature (ohm-m)
 RSH = resistivity of shale on deep log (ohm-m)
 RSHS = resistivity of shale on shallow log (ohm-m)
 RW@FT = water resistivity at form temperature (ohm-m)
 Sw = water saturation in the invaded zone (fractional)
 Sxo = water saturation in the invaded zone (fractional)
 
					
					 COMMENTS: Most analysts assume RSHS = RSH.
 Invaded
                zone water saturation is used to find the amount of hydrocarbon
                flushed by the invasion process. The hydrocarbon thus moved is
                called the moveable hydrocarbon saturation, and that left behind
                is the residual hydrocarbon saturation. A simple empirical formula
                relating water saturation and invaded zone water saturation is:1: Sxo = Sw ^ (1/5)
 This
                is a traditional relationship and local knowledge may provide
                different results. 
  Invaded
				Zone Water Saturation from Electromagnetic Logs The
				electromagnetic propagation log measures the travel time and attenuation of
                microwaves propagated along the borehole wall. The analysis concept is
                similar to a sonic log, but the frequencies involved are microwave
                (electromagnetic) in the gigahertz range instead of acoustic in
                the kilohertz range. The travel time is largely influenced by
                the amount of water in the formation and does not depend too greatly
                on other components, such as hydrocarbon or matrix rock. Because
                of its shallow investigation, the log measures the water volume
                of the flushed zones.
 The
                response equation for the electromagnetic propagation log follows
                the classical form:1:
                TP = PHIe * Sxo * TPw (water term)
 + PHIe * (1 - Sxo) * TPh (hydrocarbon term)
 + Vsh * TPsh (shale term)
 + (1 - Vsh - PHIe) * Sum (Vi * TPi) (matrix term)
 Where:TPh = log reading in 100% hydrocarbon
 TPi = log reading in 100% of the ith component of matrix rock
 TP = log reading
 TPsh = log reading in 100% shale
 TPw = log reading in 100% water
 PHIe = effective porosity (fractional)
 Sxo = water saturation in invaded zone (fractional)
 Vi = volume of ith component of matrix rock
 Vsh = volume of shale (fractional)
 The
                hydrocarbon does not contribute any signal, so the equation is
                solved directly for water filled porosity, assuming Vsh = 0.0.
                This is then compared to the total porosity, after shale volume
                corrections, based on data derived from the dual water method
                described in Section 8.11.
 
					
			 Water Satuation from EPT Method Calculate
                loss free propagation time from measured propagation time.
 1: Tpo = (TPL ^ 2 - ((ATTN - 50)) ^ 2 / 3604) ^ 0.5
  The
                value of Tpw varies with temperature and is given by:2: FT1 = SUFT + (BHT - SUFT) / BHTDEP * DEPTH)
 3: IF LOGUNITS$ = "METRIC"
 4: THEN FT1 = 9 / 5 * FT1 + 32
 5: Tpw = 20 * (710 - FT1 / 3) / (444 - FT1 / 3)
  Calculate
                water filled porosity from propagation time.6: PHIept = (Tpo - TPM) / (Tpw - TPM)
  Calculate
                water saturation of invaded zone.7: IF Vsh < 1.0
 8: THEN SWept = (PHIept - BVWSH * Vsh) / (PHIt - BVWSH * Vsh)
 9: OTHERWISE SWept = 1.0
 Where:ATTN = measured attenuation time of formation (db/m)
 BHT = bottom hole temperature (degrees Fahrenheit or Celsius)
 BHTDEP = depth at which BHT was measured (feet or meters)
 BVWsh = bulk volume water in 100% shale (fractional)
 FT1 = formation temperature (degrees Fahrenheit or Celsius)
 PHIept = total porosity from electromagnetic log (fractional)
 PHIt = total porosity from any total porosity (fractional)
 SUFT = surface temperature (degrees Fahrenheit or Celsius)
 SXOept = invaded zone saturation (fractional)
 TPL = measured propagation time of formation (nsec/m)
 TPM = loss free propagation time of matrix (nsec/m)
 Tpo = loss free propagation time of formation (nsec/m)
 Tpw = loss free propagation time of water (nsec/m)
 Vsh = volume of shale (fractional)
 
					
					 COMMENTS: In tar
				sands and heavy oil, SXOept will equal SW since there is no
				invasion in these reservoirs. This is also true in oil
				reservoirs drilled with genuine oil base mud. There may be a bit
				of invasion, but it does not change SW very much.
 Note that this value of
			SXOept does not depend on any knowledge
                of resistivity log data or assumed fluid resistivities. 
			 This
                is a thin bed tool as it sees zones of 3-4 inches in thickness Shale
                volume can be calculated from the EPT attenuation curve in a fashion
                similar to the gamma ray. This helps to resolve laminated shaly
                sands. A
                graphical solution exists but is more complicated to use than
                these simple formulae. 
                
                  |  RECOMMENDED
                    PARAMETERS: |  
                  | Material | Relative
                    Dielectric Permitivity | TPM
                    Loss-Free Propagation Time ns/m |  
                  |  |  |  |  
                  | Gas
                    or Air | 1.0 | 3.3 |  
                  | Oil | 2.2 | 4.9 |  
                  | Water | 56
                    - 80 | 25
                    - 28 |  
                  | Quartz | 4.7 | 7.2 |  
                  | Limestone | 7.5 | 9.6 |  
                  | Dolomite | 6.9 | 8.7 |  
                  | Anhydrite | 6.5 | 8.4 |  
                  | Dry
                    Clay | 5.7 | 8.0 |  
                  | Halite | 5.6
                    - 6.3 | 7.9
                    - 8.4 |  
                  | Gypsum | 4.2 | 6.8 |  
                  | Shale | 5.0
                    - 25 | 7.5 |  The
                value for water varies with temperature - see Step 5 for more
                precise values. 
					
					 NUMERICAL
				EXAMPLE: 1. Given a zone with:
 ATTN = 200 db/m
 FT = 43 degrees C = 109 degrees F
 TPL = 15 nsec/m
 TPM = 7.2 nsec/m (sandstone)
 BVWSH = 0.30
 Vsh = 0.33
 PHIe = 0.11
 Tpo = (15 ^ 2 - ((200 - 50) ^ 2) / 3604) ^ 0.5 = 11.9
 Tpw = 20 * ( 710 - 109 / 3) / (444 - 109 / 3) = 33.0
 PHIept = (11.9 - 7.2) / (33.0 - 7.2) = 0.182
 SWept = (0.182 - 0.30 * 0.33) / (0.11) = 0.75
 This
                is a reasonable number for Sxo in a sand such as Sand D.
 |